Question

How many atoms are in 2.37 moles of Krypton

Answer 1

1.43 × 10²⁴ atoms Kr

General Formulas and Concepts:

Chemistry - Atomic Structure

• Using Dimensional Analysis
• Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

Step-by-step explanation:

Step 1: Define

2.37 mol Kr

Step 2: Convert

`2.37 \ mol \ Kr((6.022 \cdot 10^(23) \ atoms \ Kr)/(1 \ mol \ Kr) )` = 1.42721 × 10²⁴ atoms Kr

Step 3: Check

We are given 3 sig figs. Follow sig fig rules and round.

1.42721 × 10²⁴ atoms Kr ≈ 1.43 × 10²⁴ atoms Kr