215k views
5 votes
A solution has a pH of 11.75. Calculate the [H:0*] of the solution

User Daveywc
by
5.1k points

1 Answer

5 votes

The [H₃0⁺] of the solution : 1.778 x 10⁻¹² M

Further explanation

pH is the degree of acidity of a solution that depends on the concentration of H⁺ ions. The greater the value the more acidic the solution and the smaller the pH.

pH = - log [H⁺]

So that the two quantities between pH and [H⁺] are inversely proportional because they are associated with negative values.

A solution whose value is different by n has a difference in the concentration of H⁺ ion of 10ⁿ.

pH of solution = 11.75

the [H₃0⁺] of the solution :


\tt pH=-log[H_3O^+]\\\\11.75=-log[H_3O^+]\\\\(H_3O^+]=10^(-11.75)=1.778* 10^(-12)

User Arthur Halma
by
5.7k points