Question

Please help me I’m struggling

Answer 1

`126.5\ ft`

Explanation:

`We\ are\ given\ that,\\Sides\ of\ the\ formed\ square=90\ ft\\As\ we\ know\ that,\\s^2+s^2=d^2[Pythagoras\ Property]\\2s^2=d^2\\Hence,\\√(2s^2) = √(d^2) \\√(2)s=d\\Hence,\\As\ the\ distance\ between\ Base\ 1\ and\ 3\ is\ the\ diagonal.\\Hence,\\The\ distance\ between\ Base\ 1\ and\ 3=√(2)*Side\\ The\ distance\ between\ Base\ 1\ and\ 3=√(2)*90\\Hence,\\`

`The\ distance\ between\ Base\ 1\ and\ 3=√(2)*√(8100) \\The\ distance\ between\ Base\ 1\ and\ 3=√(2*8100)\\The\ distance\ between\ Base\ 1\ and\ 3=√(16200)\\Hence,\\The\ distance\ between\ Base\ 1\ and\ 3=126.49\ ft\ or\ 126.5\ ft`