Question

A horizontal force of 350 NN is exerted on a 2.0-kgkg ball as it rotates (at arm's length) uniformly in a horizontal circle of radius 0.90 mm. Part A Calculate the speed of the ball. Express your answer to two significant figures and include the appropriate units.

Answer 1

The value is
`v = 12.6 \ m/s`

Step-by-step explanation:

From the question we are told that

The horizontal force is
`F_h = 350\ N`

The mass of the ball is
`m = 2.0 \ kg`

The radius is
`r = 0.90 \ m`

Generally the speed of the ball is mathematically evaluated from the formula for centripetal force as

`F_ h = (mv^2)/( r )`

=>
`v = \sqrt{( F_h * r )/( m )}`

=>
`v = \sqrt{( 350 * 0.9 )/( 2 )}`

=>
`v = 12.6 \ m/s`