Question

During a hockey game, a puck is given an initial speed of 10 m/s. It slides 50 m on the horizontal ice before it stops due to friction. What is the coefficient of kinetic friction between the pick and the ice.A) 0.12B) 0.10C) 0.11D) 0.090

Answer 1

The value is
`\mu_k = 0.102`

Step-by-step explanation:

From the question we are told that

The initial speed of the pluck is
`u = 10 \ m/s`

The distance it slides on the horizontal ice is
`s = 50 \ m`

Generally from kinematic equation we have that

`v^2 = u^2 + 2as`

Here v is is the final velocity and the value is 0 m/s given that the pluck came to rest, so

`0^2 = 10 ^2 + 2* a * 50`

=>
`a = - 1 \ m/s^2`

Here the negative sign show that the pluck is decelerating

Generally the force applied on the pluck is equal to the frictional force experienced by the pluck

So

`F = F_f`

=>
`m * a = m* g * \mu_k`

=>
`1 = 9.8 * \mu_k`

=>
`\mu_k = 0.102`