Answer:
Wavelength in water,
![\lambda=1.12* 10^6\ m](https://img.qammunity.org/2021/formulas/physics/college/m3h5cbxxpm5ct3tristqp6r5ezdr9exr7b.png)
Step-by-step explanation:
Given that,
A submarine uses sub-radio communication at 200 Hz.
The index of refraction, n = 1.333
The refractive index of a medium is given by :
![\mu=(c)/(v)\\\\\mu=(c)/(\lambda_m f)\\\\\lambda_m=(c)/(\mu f)\\\\\lambda_m=(3* 10^8)/(1.333* 200)\\\\=1.12* 10^6\ m](https://img.qammunity.org/2021/formulas/physics/college/x9uddcigye1rbjss8sxfnr1hbgy4uodkjt.png)
So, the wavelength of the electromagnetic waves in water is
.