Answer:
Small flags = 108
large flags= 47
Explanation:
Step one:
given
let the number of small lag be x
and big flags be y
so
3.5x+6.5y= 683.5----------1
x+y=155------------------------2
Step two:
from eqn 2 x= 155-y
put x= 155-y in eqn 1
3.5(155-y)+6.5y= 683.5
542.5-3.5y+6.5y=683.5
collect like terms
3y=141
divide by 3
y= 141/3
y=47
Step three:
put y= 47 in eqn 2
x+47=155
x= 155-47
x=108