Question

What is the missing fifth term in the

pattern below?

1, 8, 27, 64, ?

Options:
101
125
128
202
250

Answer 1

The answer would be 125, because 1*1 = 1 2*2*2= 8 and so forth

Explanation:

I hope this helps

Answer 2

`\huge\text{Hey there!}`

`\huge\textbf{Your equation:}`

`\mathsf{1, 8, 27, 64, ?}`

`\huge\textbf{LET'S CONVERT IT TO FOR EASIER}\\\\\huge\textbf{TO UNDERSTAND A WHOLE LOT}\\\\\huge\textbf{BETTER.}`

`\mathsf{1^3, 2^3, 3^3, 4^3, ?}`

`\huge\textbf{Notice the pattern?}\\\\\\\\\huge\textbf{So, that means your mystery number}\\\\\huge\textbf{has to be squared (also known as to the}\\\\\huge\textbf{power of 3}`

`\huge\textbf{Breaking down the exponents}`

`\mathsf{1^3}\\\mathsf{= 1*1*1}\\\mathsf{= 1*1}\\\mathsf{= \bf 1}`

`\mathsf{2^3}\\\mathsf{= 2*2*2}\\\mathsf{= 4*2}\\\mathsf{= \bf 8}`

`\mathsf{3^3}\\\mathsf{= 3*3*3}\\\mathsf{= 9*3}\\\mathsf{= \bf 27}`

`\mathsf{4^3}\\\mathsf{= 4*4*4}\\\mathsf{= 16*4}\\\mathsf{= \bf 64}`

`\huge\textbf{If you didn't notice that your}\\\\\huge\textbf{exponents went like 1,2,3,4.}\\\\\\\\\huge\textbf{so that your mystery number has to}\\\\\huge\textbf{be 5 squared}`

`\mathsf{5^3}\\\mathsf{= 5*5*5}\\\mathsf{= 25*5}\\\mathsf{=125}`

`\huge\textbf{The result:}`

`\huge\boxed{\mathsf{Option\ B. \ 125}}\huge\checkmark`

`\huge\textbf{The outro}`

`\huge\textbf{Signature}`

~
`\huge\boxed{\frak{Amphitrite1040:)}}`