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What is the equation of the line that is perpendicular to y=x+4 and that passes through (5,-4)?
--5v-20
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User Webmato
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1 Answer

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Perpendicular lines have slopes that are negative reciprocals of each other, so since the slope of the given line is 1, the slope of the line we want to find is -1.

Substituting into point-slope form,


y+4=-1(x-5)\\\\y+4=-x+5\\\\\boxed{y=-x+1}

2 What is the equation of the line that is perpendicular to y=x+4 and that passes-example-1
User Robert Ilbrink
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