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A gorilla weighs 8.00x10^2N and swings from vine to vine. As the gorilla grads a new vine, both vines make an angle of 30 degrees with the verticle. In such a condition of static equillibrium what is the
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A gorilla weighs 8.00x10^2N and swings from vine to vine. As the gorilla grads a new vine, both vines make an angle of 30 degrees with the verticle. In such a condition of static equillibrium what is the net force on the vine?

User Mozy
by
4.7k points

2 Answers

3 votes

Answer:

hi

Step-by-step explanation:

User Asfar Irshad
by
4.4k points
2 votes

Answer:

461.88 N

Step-by-step explanation:

Let tension in each vine be T .

The vertical component of this tension of both the vine will add up and balance the weight .

2T cos 30 = mg

2 T x cos 30 = 800

T = 800 / (2 x cos30 )

= 461.88 N

User Anis Tissaoui
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5.5k points
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