![\sf{\qquad\qquad\huge\underline{{\sf Answer}}}](https://img.qammunity.org/2023/formulas/mathematics/college/on7gka1wo2txyyqda4lpzjucown6bxp6mo.png)
Let's solve for x and z ~
![\qquad \sf \dashrightarrow \: z + 68 = 180](https://img.qammunity.org/2023/formulas/mathematics/high-school/x8uf2u176ngmk5y1pxyc7iqngbmtwpq18p.png)
[ they form co - exterior angle pair ]
![\qquad \sf \dashrightarrow \: z = 180 - 68](https://img.qammunity.org/2023/formulas/mathematics/high-school/lga1osygk3dmonsi2i7z4trdo5e34mke7e.png)
![\qquad \sf \dashrightarrow \: z = 112 \degree](https://img.qammunity.org/2023/formulas/mathematics/high-school/fw10wwamryr8ri9mlvpfhhdirvqoo2dn0n.png)
now, it's time for x :
First angle z is equal to its vertical opposite angle, and then that angle forms co - interior angle pair with (3x - 28)
![\qquad \sf \dashrightarrow \: 3x - 28 + 112 = 180](https://img.qammunity.org/2023/formulas/mathematics/high-school/mxwycggyxu61khdiv54micptudgf3zf7zf.png)
![\qquad \sf \dashrightarrow \: 3x + 84 = 180](https://img.qammunity.org/2023/formulas/mathematics/high-school/m43nkm0bo20ciwnuvahwatwjxe8jm7cecc.png)
![\qquad \sf \dashrightarrow \: 3x = 180 - 84](https://img.qammunity.org/2023/formulas/mathematics/high-school/d5o062coisuv1jpj8a52rmfruwg4ro59sq.png)
![\qquad \sf \dashrightarrow \: 3x = 96](https://img.qammunity.org/2023/formulas/mathematics/high-school/ufe491ps82nf0u9j6xitgd3yh489ord6k1.png)
![\qquad \sf \dashrightarrow \: x = 96 / 3](https://img.qammunity.org/2023/formulas/mathematics/high-school/z6q77rgo8quanlx0pup54207e8fjq2r4di.png)
![\qquad \sf \dashrightarrow \: x = 32 \degree](https://img.qammunity.org/2023/formulas/mathematics/high-school/c9gg0x4yhf79by442u7x84wtkl5wu299vd.png)
That's all... let me know if you have questions ~