Answer:
![(1)/(10)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/s1nk8ftomqwqljr3bnh1epjpogskrs6plr.png)
Explanation:
Given: The bag has 5 green chips, 3 red chips, and 7 blue chips.
Total chips = 5+3+7= 15
Number of ways to select a red and then a blue chip = 3 x 7 = 21
Total number of ways to select 2 chips without replacement = 15 x 14 =210
Required probability =
![\frac{\text{favorable outcomes}}{\text{Total outcomes}}](https://img.qammunity.org/2021/formulas/mathematics/college/xl91a75tswgk4yfo3exk8cakw7mg8lv77b.png)
![=(21)/(210)=(1)/(10)](https://img.qammunity.org/2021/formulas/mathematics/high-school/icswtrywninre1ch3qj8ttonyj6r6rzx2e.png)
So, the probability that he selects a red and then a blue chip (without replacing) =
![(1)/(10)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/s1nk8ftomqwqljr3bnh1epjpogskrs6plr.png)