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AD is a diameter of circle ABCDE . Angle BAC=22° & angle ADC=60°. AE and ED are parallel lines. Find the values of w, x,y,and z

AD is a diameter of circle ABCDE . Angle BAC=22° & angle ADC=60°. AE and ED are-example-1
User Aledpardo
by
5.4k points

1 Answer

1 vote

Answer:

x = 22°

w = 30°

y = 30°

z = 52°

Explanation:

From ΔACD,

AD is the diameter and ∠ACD is the angle subtended by the diameter.

Therefore, m∠ACD = 90°

By triangle sum theorem,

m∠DAC + m∠ACD + m∠CDA = 180°

w° + 90° + 60° = 180°

w = 180 - 150

w = 30°

AB║ED and AD is a transversal line.

Therefore, m∠BAD = m∠ADE

(w + 22)° = z°

30 + 22 = z

z = 52°

Since, ∠CEB and ∠BAC are the inscribed angles subtended by the same arc BC,

Therefore, m∠CEB = m∠BAC

x = 22°

Similarly, ∠CED and ∠DAC are the inscribed angles subtended by the same arc CD,

m∠CED = m∠DAC = 30°

y = 30°

User Fatfatson
by
4.9k points
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