Question

Use the balanced equation given below to solve the following problem; Calculate the volume in liters of CO produced by the reaction of 175 g of Sb2O3.

Sb2O3 + 3 C --> 2 Sb + 3 CO

40.3 L CO
7.81 L CO
20.2 L CO
13.4 L CO

Answer 1

Answer: 40.3 L

Step-by-step explanation:

To calculate the moles :

`\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}`

`\text{Moles of} Sb_2O_3=(175g)/(291.5g/mol)=0.600moles`

`Sb_2O_3+3C\rightarrow 2Sb+3CO`

According to stoichiometry :

1 moles of
`Sb_2O_3` produces = 3 moles of
`CO`

Thus 0.600 moles of
`Sb_2O_3` will produce=
`(3)/(1)* 0.600=1.80moles` of
`CO`

Volume of
`CO=moles* {\text {Molar volume}}=1.80moles* 22.4L/mol=40.3L`

Thus 40.3 L of CO is produced.