171k views
4 votes
Solve the following simultaneous equations:

5logx 16 – 2log9 y = 19
3logx 16 + 4log9 y = 14
URGENT

User ThePeter
by
6.0k points

1 Answer

2 votes

Answer:

x = 2

y = 3

Step-by-step explanation:


5log_x16-2log_9Y=19\ \ --->Equation\ 1\\\\3log_x16+4log_9Y=14\ \ --->Equation\ 2\\

Take e\Equation 1


5log_x16-2log_9Y=19\\


5log_x16=19+2log_9Y\\\\log_x16=(19+2log_9Y)/(5) --->Equation\ 3

Put Equation 3 in Equation 2


3log_x16+4log_9Y=14\\\\3((19+2log_9Y)/(5))+4log_9Y=14 \\\\(57+6log_9Y)/(5)+4log_9Y=14\\\\(57+6log_9Y+20log_9Y)/(5) =14


57+6log_9Y+20log_9Y=70\\\\26log_9Y=70-57\\\\26log_9Y=13\\\\log_9Y=0.5\\\\y=3\\

We got the value of y = 3 now insert y = 3 in Equation 3


log_x16=(19+2log_9Y)/(5) \\\\log_x16=(19+2log_93)/(5) \\\\log_x16=(19+log_93^2)/(5) \\\\log_x16=(19+log_99)/(5) \\\\log_x16=(19+1)/(5) \\\\log_x16=4


x =2

So we got x =2 and y =3

User Dagrada
by
6.8k points