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PLEASE HELPPPP

What is the equation of the line that passes through the point (4, -4) and has a
slope of ?

PLEASE HELPPPP What is the equation of the line that passes through the point (4, -4) and-example-1
User El Diablo
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1 Answer

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Answer:


y = -(5)/(2)x + 6

Explanation:

Using a point (4, -4) and the slope of the line that passes through it, m = -⁵/2, we can generate an equation by using the point-slope form equation of a line given as y - b = m(x - a).

Where,

(a, b) = (4, -4)

m = -⁵/2

Plug in the values

y - (-4) = -⁵/2(x - 4)

y + 4 = (-5x + 20)/2

Multiply both sides by 2

2y + 8 = -5x + 20

Subtract both sides by 8

2y = -5x + 20 - 8

2y = -5x + 12

Divide both sides by 2

y = -⁵/2x + 12/2


y = -(5)/(2)x + 6 (equation in slope-intercept form)

User Jeril Kuruvila
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5.0k points