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Solve (x^3-4x)(2x^2-3x)​
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Solve (x^3-4x)(2x^2-3x)​

User Jason Coon
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1 Answer

3 votes

Answer:

= x^2 ( 2x^3- 3x^2 - 8x + 12)

Explanation:

(x^3-4x) (2x^2-3x)

= x^3(2x^2-3x) -4x(2x^2-3x)

= 2x^5-3x^4-8x^3+12x^2

= x^2 ( 2x^3- 3x^2 - 8x + 12)

User Kerim Khasbulatov
by
5.7k points
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