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Consider the following reaction.

2Fe2O3(s)+3C(s)−→−heat4Fe(s)+3CO2(g)
Calculate the number of grams of Fe2O3 needed to react with 18.3 g C.

1 Answer

7 votes

Answer:

162 g Fe₂O₃

Step-by-step explanation:

To find the mass of Fe₂O₃, you need to (1) convert grams C to moles C (via molar mass from periodic table), then (2) convert moles C to moles Fe₂O₃ (via mole-to-mole ratio from reaction coefficients), and then (3) convert moles Fe₂O₃ to grams (via molar mass). It is important to arrange the ratios/conversions in a way that allows for the cancellation of units. The final answer should have 3 sig figs to reflect the given value.

Molar Mass (C): 12.011 g/mol

2 Fe₂O₃(s) + 3 C(s) ---> 4 Fe(s) + 3 CO₂(g)

Molar Mass (Fe₂O₃): 2(55.845 g/mol) + 3(15.998 g/mol)

Molar Mass (FeO): 159.684 g/mol

18.3 g C 1 mole 2 moles Fe₂O₃ 159.684 g
-------------- x ---------------- x ------------------------- x ----------------- = 162 g FeO
12.011 g 3 moles C 1 mole

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