Question

Consider the equation 10 2z/3=15.

solve the equation for z.
express the solution as a logarithm base-10
z=
approximate the value of z. round your answer to the nearest thousandth
z=

Answer 1

z= 3log(15)/2

z= 1.764

Answer 2

Hi there! :)

`\large\boxed{z = 1.764}`

`10x^((2z/3)) = 15`

Rewrite as a logarithmic equation using this format:

`a^(b) = c \\\\log_(a)c = b`

In this instance:

a = 10 (log is by default base 10)

b = 2z / 3

c = 15

Rewrite as the log equation:

`log 15 = 2z/3`

Evaluate log (15):

`1.176 = 2z / 3`

Multiply both sides by 3:

`3.528 = 2z`

Divide both sides by 2:

`z = 1.764`