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MZACB = (6y-7)° and mZDCA = (8y - 1)°.
B
A
D
|
C
What is mZACB?

MZACB = (6y-7)° and mZDCA = (8y - 1)°. B A D | C What is mZACB?-example-1
User Shikiju
by
5.9k points

1 Answer

8 votes

Answer:
35^(\circ)

Explanation:

Angles ACB and DCA add to form angle ACB, which is a right angle, so:

  • 6y - 7 + 8y - 1 = 90 [angles that add to form a right angle add to 90 degrees]
  • 14y - 8 = 90 [combine like terms]
  • 14y = 98 [add 8 to both sides]
  • y = 7 [divide both sides by 14]

So,
m\angle ACB=6(7)-7=\boxed{35^(\circ)}

User Rohan Patel
by
6.2k points