Question

if you started with 2.34 grams of methane and 8.32 grams of oxeygyn and the combustion reaction went to completion how many grams of CO2 would be produced

Answer 1

Mass of CO₂ produced = 5.72 g

Step-by-step explanation:

Given data:

Mass of methane = 2.34 g

Mass of oxygen = 8.32 g

Mass of CO₂ produced = ?

Solution:

Chemical equation:

CH₄ + 2O₂ → CO₂ + 2H₂O

Number of moles of methane:

Number of moles = mass/molar mass

Number of moles = 2.34 g/ 16 g/mol

Number of moles = 0.146 mol

Number of moles of oxygen:

Number of moles = mass/molar mass

Number of moles = 8.32 g/ 32 g/mol

Number of moles = 0.26 mol

Now we will compare the moles of carbon dioxide with oxygen and methane.

CH₄ : CO₂

1 : 1

0.146 : 0.146

O₂ : CO₂

2 : 1

0.26 : 1/2×0.26 = 0.13 mol

Less number of moles of CO₂ are produced by oxygen thus oxygen will react as limiting reactant.

Mass of CO₂:

Mass = number of moles × molar mass

Mass = 0.13 mol × 44 g/mol

Mass = 5.72 g