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Which expression is equivalent to (tan(theta/2))(-sin theta)

User NarfkX
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11 votes

Answer:

Explanation:


(tan(\theta)/(2) )(-sin\theta)\\=((sin~(\theta)/(2) )/(cos(\theta)/(2) ) )(-2sin(\theta)/(2) cos(\theta)/(2))\\=-2sin ^2 (\theta)/(2) \\=cos ~2 \theta-1

User Atabrizi
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