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User Ashad
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1 Answer

4 votes

Answer:

a) 67

b) x= -8 and 4

c) 31

Explanation:

a) if m<1 = (6x - 5) and m<5 = (5x+7), find m<3.

6x - 5 = 5x + 7

-5x + 5 - 5x + 5

x = 12

6(12) - 5 = 5(12) + 7

72 - 5 = 60 + 7

67 = 67

b) if m<4 = 32 and m<8 = (x^2 - 4x), find x.

32 = x^2 - 4x

- 32 - 32

x^2 - 4x - 32

(x - 8)(x + 4)

x - 8 = 0 x + 4 = 0

+ 8 + 8 - 4 - 4

x = -8 and 4

c) if m<4 = (4x - 17) and m<5 = (5x - 29), find m<1.

4x - 17 = 5x - 29

-5x + 17 -5x + 17

-x = -12

/-1 /-1

x = 12

4(12) - 17 = 5(12) - 29

48 - 17 = 60 - 29

31 = 31

User UserBG
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