Explanation:
I am not sure I can see the room limitations.
what I see is that the kitchen is one large rectangle from
(-8, 8) to (0, 0).
the rec room is Amado one large rectangle from
(5, 6) to (8, -7).
I am basing the rest in this.
for the area calculations, please consider that the area of a rectangle is length × width, and the area of a triangle is half of the rectangle it splits in half with its baseline (as diagonal).
A)
area 1 =
rectangle (-8, 8) to (-5, 3)
plus
half of the rectangle (-5, 8) to (-3, 3)
3×5 + 1/2 × 2×5 = 3×5 + 1×5 = 15 + 5 = 20 yd²
area 2 =
half of the rectangle (-5, 8) to (-3, 3)
plus
rectangle (-3, 8) to (0, 3)
1/2 × 2×5 + 3×5 = 20 yd²
area 3 = area 4 =
half of the rectangle (-8, 3) to (0, 0)
1/2 × 8×3 = 4×3 = 12 yd²
B)
the total area of the kitchen is the sum of all 4 areas
20 + 20 + 12 + 12 = 64 yd²
we can also calculate this in general, seeing that the general dimensions of the kitchen are 8×8 : from (-8, 8) to (0, 0).
8×8 = 64 yd²