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Ldentify an equation in point-slope form for the line perpendicular to

y=-4x- 1 that passes through (-2, 7).
OA. y-7= -4(x+2)
O B. y+7= -1/4(x-2)
Oc. y+2= 1/4 (x-7)
OD. y-7= 1/4(x+2)

Ldentify an equation in point-slope form for the line perpendicular to y=-4x- 1 that-example-1
User Mayron
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1 Answer

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Answer:

D

Explanation:

The given line's equation is in slope-intercept form:

y = mx + b

where m = -4 is the slope, and b = -1 is the y-intercept.

The slope of the perpendicular line will be ...

-1/m = -1/(-4) = 1/4

You want the point-slope equation for the line, which is ...

y -k = m(x -h) . . . . line with slope m through point (h, k)

Your equation will have m=1/4, (h, k) = (-2, 7), so it will be ...

y -7 = 1/4(x +2)

Ldentify an equation in point-slope form for the line perpendicular to y=-4x- 1 that-example-1
Ldentify an equation in point-slope form for the line perpendicular to y=-4x- 1 that-example-2
User ZedTuX
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5.5k points