Question

How do you put f(8)=-1,f(6)=0 into point slop form?​

Answer 1

y + 1 = -1/2(x - 8)

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

1. Brackets
2. Parenthesis
3. Exponents
4. Multiplication
5. Division
6. Addition
7. Subtraction

• Left to Right

Algebra I

Slope Formula:
`m=(y_2-y_1)/(x_2-x_1)`

Point-Slope Form: y - y₁ = m(x - x₁)

• x₁ - x coordinate
• y₁ - y coordinate
• m - slope

Explanation:

Step 1: Define

f(8) = -1 → Coordinate (8, -1)

f(6) = 0 → Coordinate (6, 0)

Step 2: Find slope m

1. Substitute [SF]:
   `m=(0+1)/(6-8)`
2. Add/Subtract:
   `m=(1)/(-2)`
3. Simplify:
   `m=(-1)/(2)`

Step 3: Write Function

Substitute into general form.

• Point 1: y + 1 = -1/2(x - 8)
• Point 2: y = -1/2(x - 6)