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If a solution containing 86.04 g of mercury(II) nitrate is allowed to react completely with a solution containing 15.488 g of sodium sulfide, how many grams of solid precipitate will be formed
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If a solution containing 86.04 g of mercury(II) nitrate is allowed to react completely with a solution containing 15.488 g of sodium sulfide, how many grams of solid precipitate will be formed

User Vlad Ankudinov
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Given: Weight of mercury perchlorate is 100.82 g Weight of sodium sulphide is 17.796 g Solution: The chemical equation for the reaction of mercury(II)perchl ... More

User Nkem
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