Question

What is the slope of the line that passes through the points (8,-8) and (5,-1)?

Answer 1

SOLVING

`\Large\maltese\underline{\textsf{A. What is Asked}}`

What is the slope of a linear function that goes through (8,-8) and (5,-1)?

`\Large\maltese\underline{\textsf{B. This problem has been solved!}}`

Formula utilised, here
`\bf{(y2-y1)/(x2-x1)}`.

We utilise that formula because we have two points as our given information.

So, we

put in the values

`\bf{(-1-(-8))/(5-8)}` | subtract on top and bottom

`\bf{(-1+8)/(-3)}` | simplify

`\bf{(7)/(-3)`

`\cline{1-2}`

`\bf{Result:}`

`\bf{=Slope=-(7)/(3)}`

`\LARGE\boxed{\bf{aesthetic\\ot1\theta l}}`

Answer 2

Hey there!

• Answer :

`\sf{ \purple{ \boxed{\bold{m = - (7)/(3) }}}}`

`\\`

• Explanation :

We are given the points
`\sf{P_1(\overbrace{ \blue{8}}^{\blue{x_1}} ,\underbrace{\orange{-8}}_{ \orange{y_1}}) \: and \: P_2(\overbrace{ \green{5}}^{\green{x_2}} ,\underbrace{\red{-1}}_{\red{y_2} })}` . To find the slope
`\sf{\purple{m}}` of such a line, we use the slope formula which is the following:

`\sf{ \purple{m} }= (\Delta y)/(\Delta x) = \frac{ \red{y_2} - \orange{y_1}}{ \green{x_2 }- \blue{x_1}}`

`\\`

⇢Now, by plugging in our values, we get :

`\sf{ \purple{m}} = \frac{ \red{ - 1} - \orange{( - 8)}}{ \green{5} \: - \: \blue{8}} = ( \: \: 7 \: )/( - 3 \: ) \\ \\ \implies \sf{ \purple{ \boxed{m = - (7)/(3) }}}`

Therefore, the slope of the line is
`\sf{ \purple{ \boxed{m = - (7)/(3) }}}`