Question

What are the zeros of the quadratic function f(x)=6x^2+12x-7

Answer 1

`A) \ x=-1 \ ^ +_-(√(13) )/(√(6)).`

Explanation:

if to solve the given equation, then

D=6²+42=78;

`\left[\begin{array}{ccc}x=(-6-√(78))/(6) \\x=(-6+√(78))/(6) \end{array} \ = > \ \left[\begin{array}{ccc}x=-1-\sqrt{(13)/(6) } \\x=-1+\sqrt{(13)/(6) } \end{array}`