Question

Find an equation of the line that passes through (3,10) and is parallel to the line x-3y=1

Answer 1

-27...............sidoofkendff

Answer 2

x - 3y = -27

Explanation:

Two parallel lines have equations of the same form; only the constants differ.

Thus, if the given line is x - 3y = 1, the desired new line has equation of the form x - 3y = C, where we must find the value of C.

Substituting 3 for x and 10 for y in x - 3y = C, we get 3 - 3(10) = C, or

3 - 30 = C. Thus, C = -27 and the desired new line is x - 3y = -27.