Question

1-4x/2x+1=4/1-5x
solve in quadratic equations​

Answer 1

I can only assume that the entire 1-4x is divided by 2x, and 4 by all of 1 - 5x. You can guarantee more accurate results by using brackets where appropriate. If I read that expression with the correct notation, it reads as
`1 - (4x)/(2x) + 1 = (4)/(1) - 5x`.

Assuming instead that it's meant as
`(1 - 4x)/(2x + 1) = (4)/(1 - 5x)`, we can solve it as shown below, giving us x values of 1 and 3/20 (or 0.15).

Explanation:

First let's reformat this to the usual ax² + bx + c format:

`(1 - 4x)/(2x + 1) = (4)/(1 - 5x)\\(1 - 4x)(1 - 5x) = 4(2x + 1)\\1 - 5x - 4x + 20x^2 = 8x + 4\\20x^2 - 5x - 4x - 8x + 1 - 4 = 0\\20x^2 - 17x - 3 = 0`

Let's solve it with the quadratic formula:

`x = (-b \pm √(b^2 - 4ac) )/(2a)\\\\x = (17 \pm √(-17^2 - 4* 20 *( -3)) )/(2*20)\\\\x = (17 \pm √(289 + 240) )/(40)\\\\x = (17 \pm 23 )/(40)\\\\x = 1, (3)/(20)`