Question

A new community is being built in del rio . The perimeter of the rectangular playing field is 562 yards . The length of the field is 9 yards less than quadruple the width . What are the dimensions of the playing field ?

Answer 1

223yd by 58yd

Explanation:

Perimeter of the rectangular field P = 2L + 2W

L is the length

w is the width

If the length of the field is 9 yards less than quadruple the width then;

L = 4w - 9

Substitute L = 4w - 9 into the formula for perimeter;

P = 2(4w-9)+ 2w

562 = 8w-18+2w

562 = 10w-18

10w = 562+18

10w = 580

w = 58

Since L = 4w - 9

L = 4(58)-9

L = 223yards

Hence the dimension of the field is 223yd by 58yd