Question

An airplane wing is designed so that the speed of the air across the top of the wing is 297 m/s when the speed of the air below the wing is 209 m/s. The density of the air is 1.29 kg/m3. What is the lifting force on a wing of area 26.0 m2?

Answer 1

The value is
`F_L = 759200 \ N`

Step-by-step explanation:

From the question we are told that

The speed of air across the top of its wings is
`v = 297 \ m/s`

The speed of air below its wings is
`u = 209 \ m/s`

The density of air is
`\rho = 1.29 \ kg/m^3`

The area of the wing is
`A = 26.0 \ m^2`

Generally the lifting force is mathematically represented as

`F_L = \Delta P * A`

Here
`\Delta P` is the difference in kinetic energy density between the top and the bottom

`\Delta P = (1)/(2) * \rho * [v^2 - u^2 ]`

=>
`\Delta P = (1)/(2) * 1.29 * [297^2 - 209^2 ]`

=>
`\Delta P = 2.92 *10^(4) \ Pa`

So

`F_L = 2.92 *10^(4) * 26.0`

=>
`F_L = 759200 \ N`