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For constant volume processes the heat capacity of gas A is greater than the heat capacity of gas B. We conclude that when they both absorb the same energy as heat at constant volume:

A. the temperature of A increases more than the temperature of B
B. the temperature of B increases more than the temperature of A
C. the internal energy of A increases more than the internal energy of B
D. the internal energy of B increases more than the internal energy of A
E. A does more positive work than B

User Dems
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Answer:

B). the temperature of B increases more than the temperature of A

Step-by-step explanation:

For constant volume process, relation between molar heat capacity and temperature is given by,


$\Delta Q = mC_v \Delta T$

where, ΔQ is the amount of heat required

m is the mass of the gas


$C_v$ is heat capacity at constant volume

ΔT is the change in temperature.

For a constant energy ΔQ,


$C_v=(1)/(\Delta T)$

Given,
$(C_v)_A>(C_v)_B$


$(\Delta T)_A < (\Delta T)_B $

Thus the temperature of gas B increases more than the temperature of gas A.

User Bondenn
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