Answer:
0.36M HCl
Step-by-step explanation:
The reaction of Mg(OH)₂ with HCl is:
Mg(OH)₂ + 2HCl → MgCl₂ + 2H₂O
Where 1 mole of magnesium hydroxide reacts with 2 moles of HCl
To solve this question, we need to find the moles of Mg(OH)₂ that reacted and, with chemical equation, solve for the moles of HCl and its molarity (Using the 10.00mL = 0.01000L) as follows:
Moles of Mg(OH)₂:
18mL = 0.018L * (0.100mol / L) = 0.0018 moles Mg(OH)₂
Moles HCl:
0.0018 moles Mg(OH)₂ * (2 moles HCl / mol Mg(OH)₂) = 0.0036 moles HCl
Molarity HCl:
0.0036 moles HCl / 0.0100L =
0.36M HCl