Question

The question is:

Jason has 20 gallons of a 12% alcohol solution. How many gallons, to the nearest tenth, must be replaced by a 36% alcohol solution to give 20% gallons of 15% alcohol solution.

I need and explanation on how to set it up and do it. I have a test today and I don’t understand it.

Answer 1

2.5 gallons of the 20% solution must be replaced by the 36% solution.

Explanation:

`.12(20 - x) + .36x = 20(.15)`

`2.4 - .12x + .36x = 3`

`2.4 - .24x = 3`

`- .24x = - .6`

`.24x = .6`

`x = 2.5`