Question

A worker receives uniform, whole-body doses of 0.30 mGy from 100-keV neutrons, 0.19 mGy from 1.5-MeV neutrons, and 4.3 mGy from gamma rays. Calculate the effective dose

Answer 1

The effective dose is
`E = 11.1\ mS_v`

Step-by-step explanation:

From the question we are told that

The whole-body does received from 100-keV neutrons is
`D_1 = 0.30 mGy = 0.30 *10^(-3) \ Gy`

The whole-body does received from 1.5-MeV neutrons is
`D_2 = 0.19 mGy = 0.19 *10^(-3) \ Gy`

The whole-body does received from gamma rays is
`D_3= 4.3 mGy = 4.3 *10^(-3) \ Gy`

Generally from the table of radiation weight factor ,

The radiation weight factor for 100-keV neutrons is
`R_1 = 10`

The radiation weight factor for 100-keV neutrons is
`R_2 = 20`

The radiation weight factor for gamma rays is
`R_3 = 1`

Generally the effective does is mathematically represented as

`E = R_1 * D_1 + R_2 * D_2 + R_3 * D_3`

=>
`E = 10 * 0.30 +20 * 0.19 +1 * 4.3`

=>
`E = 11.1\ mS_v`