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Write parametric equations of the line through the points (7,1,-5) and (3,4,-2). please use the first point as your base-point when writing the equations.

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Given:

A line through the points (7,1,-5) and (3,4,-2).

To find:

The parametric equations of the line.

Solution:

Direction vector for the points (7,1,-5) and (3,4,-2) is


\vec {v}=\left<x_2-x_1,y_2-y_1,z_2-z_1\right>


\vec {v}=\left<3-7,4-1,-2-(-5)\right>


\vec {v}=\left<-4,3,3\right>

Now, the perimetric equations for initial point
(x_0,y_0,z_0) with direction vector
\vec{v}=\left<a,b,c\right>, are


x=x_0+at


y=y_0+bt


z=z_0+ct

The initial point is (7,1,-5) and direction vector is
\vec {v}=\left<-4,3,3\right>. So the perimetric equations are


x=(7)+(-4)t


x=7-4t

Similarly,


y=1+3t


z=-5+3t

Therefore, the required perimetric equations are
x=7-4t, y=1+3t and
z=-5+3t.

User Siva Kandaraj
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