112k views
4 votes
Trapezoid A B C D is shown. A diagonal is drawn from point B to point D. Sides B C and A D are parallel. Sides B A and C D are congruent. Angle C B D is 24 degrees and angle B A D is 116 degrees. What is the measure of angle ABD in trapezoid ABCD? 24° 40° 64° 92

User Keego
by
8.5k points

2 Answers

2 votes

Answer:

40

Explanation:

its right

User Osama Naeem
by
8.3k points
6 votes

Answer:

40 degrees

Explanation:

The given trapezoid ABCD is shown in the figure, in which sides BC and AD are parallel.

Angle CBD=24 degrees.

Angle BAD=116 degrees.

As the diagonal BD cuts the two parallel sides BC and AD, so

Angle CBD = Angle ADB [alternate angles]

So, Angle ADB= 24 degrees.

Now, in the triangle ABD, the sum of all the three angles,

Angle ABD + Angle ADB + Angle BAD =180 degrees.

Angle ABD + 24 degrees + 116 degrees =180 degrees

So, Angle ABD= 180 - 24 - 116= 40 degrees.

Hence, Angle ABD = 40 degrees.

Trapezoid A B C D is shown. A diagonal is drawn from point B to point D. Sides B C-example-1
User Najeira
by
7.2k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories