Answer:
The chances of Yvonne to get a blue berry candy in the two cases are 1 and 1/2 in case 1 and 2/3 in the case 2.
Explanation:
Maurice has a paper bag with three hard candies
2 blueberries and 1 green apple
Yvonne and Kate want 1 candy each
It is not mentioned that ether Kate has taken a candy already before Yvonne or not so we will consider both the cases
Case 1
If Kate has picked a candy before Yvonne
- If Kate gets an Apple green candy then the probability or Yvonne to get a Blueberry will be = 2/2 = 1 ( as there will 2 blueberry candy left in the bag)
- If Kate has taken a Blueberry candy then there will be 1 blueberry and 1 apple green candy in the bag so the probability of Yvonne to get a Blueberry candy will be = 1/2
Case 2
If Kate has not taken any candy from the bag before Yvonne
Probability that Yvonne will get a blueberry candy will be = 2/3
Therefore the chances of Yvonne to get a blue berry candy in the two cases are 1 and 1/2 in case 1 and 2/3 in the case 2.