Question

What is te equation of the line that passes through the point (6, -5) and is perpendicular to the line represented by y= 3/4x +2?

Help me pls

Answer 1

y=Mx+c
Since both lines are perpendicular, then their product is -1
y = 3/4x. +. 2
M= 3/4
M. M2 = -1
3/4 . M2 = -1
M2 = -4/3

M2=y-y1/x- x2
Since th
M2=y - (-5). /. x- 6
-4/3 = y+5. / x-6
-4(x-6) = 3(y+5)
-4x + 24 = 3y + 15
3y= -4x+24-15
3y = -4x + 9
y= -4/3x + 3


Answer is y= -4/3x + 3