Question

Please can someone write the answers and tell me how you get it in a notebook please

Answer 1

Given:

`6x+3y=12`

`2x-6y=18`

`5x+2y=16`

`6x-8y=-24`

To find:

The slope intercept form of each equation.

Solution:

We know that, slope intercept form of a line is

`y=mx+b`

where, m is slope and b is y-intercept.

The first equation is

`6x+3y=12`

Subtract 6x from both sides.

`3y=12-6x`

Divide both sides by 3.

`y=(12-6x)/(3)`

`y=(12)/(3)-(6x)/(3)`

`y=4-2x`

`y=-2x+4`

Therefore, the slope intercept form of first equation is
`y=-2x+4`.

Similarly,

`2x-6y=18`

`-6y=18-2x`

`y=(18-2x)/(-6)`

`y=-3+(1)/(3)x`

`y=(1)/(3)x-3`

Therefore, the slope intercept form of second equation is
`y=(1)/(3)x-3`.

`5x+2y=16`

`2y=16-5x`

`y=(16-5x)/(2)`

`y=8-(5)/(2)x`

`y=-(5)/(2)x+8`

Therefore, the slope intercept form of third equation is
`y=-(5)/(2)x+8`.

`6x-8y=-24`

`-8y=-24-6x`

`y=(-24-6x)/(-8)`

`y=(-24)/(-8)-(6x)/(-8)`

`y=3+(3)/(4)x`

`y=(3)/(4)x+3`

Therefore, the slope intercept form of fourth equation is
`y=(3)/(4)x+3`.