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What are the

Solutions of 3x' -x+7 =0?

A. x-2+İN83 or x- 2- i88
B. X-1+N83 orx= 1-iN88
C. x- 1+9/ or x 1-9;
D. X- 2+9i or x- 2-9/

What are the Solutions of 3x' -x+7 =0? A. x-2+İN83 or x- 2- i88 B. X-1+N83 orx= 1-iN-example-1
User Datchung
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1 Answer

1 vote

Answer:

x = 1+√83 i/6 and 1-√83 i/6

Explanation:

Given the quadratic expression;

3x^2-x+7 =0

Using the general foemula to find x

x = -b±√b²-4ac/2a

From the equation

a = 3, b = -1 and c = 7

Substitute

x = -(-1)±√(1)²-4(3)(7)/2(3)

x = 1±√1-84/6

x = 1±√-83/6

x = 1±√83 i/6

x = 1+√83 i/6 and 1-√83 i/6

User Samnu Pel
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