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P ⇒ q, r ⇒ s, p ∨r q ∧ s is invalid
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P ⇒ q, r ⇒ s, p ∨r q ∧ s is invalid

User Nils Schmidt
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1 Answer

5 votes

Answer:

My explanation and answer are down here↓:

Step-by-step explanation:

p→q is false only when p is true and q is false.

∴p→(q∨r) is false when p is true and (q∨r) is false, and

q∨r false when both q,r are false.

Hence T,F,F.

User Douglas Leeder
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