Given:
The equation is
![y=-1(x-4.5)^2+15.25](https://img.qammunity.org/2021/formulas/mathematics/high-school/fz7s03kp9um7fekrf6xzsuizpm0fvkdjkj.png)
To find:
The standard form of the given equation.
Solution:
We have,
![y=-1(x-4.5)^2+15.25](https://img.qammunity.org/2021/formulas/mathematics/high-school/fz7s03kp9um7fekrf6xzsuizpm0fvkdjkj.png)
It is a quadratic equation.
The standard form of a quadratic equation is
. So, we need to write the given equation in this form.
![y=-(x-4.5)^2+15.25](https://img.qammunity.org/2021/formulas/mathematics/high-school/t84s4g1yl99p739e39c90aq0tt4nzminvj.png)
![[\because (a-b)^2=a^2-2ab+b^2]](https://img.qammunity.org/2021/formulas/mathematics/high-school/ns8xcknd2la2h0fgcz5pt0lrf7e0cp5mva.png)
![y=-[x^2-9x+20.25]+15.25](https://img.qammunity.org/2021/formulas/mathematics/high-school/b8h77fu8zhax1dk53maa55wwhps2ga29g3.png)
![y=-x^2+9x-20.25+15.25](https://img.qammunity.org/2021/formulas/mathematics/high-school/898t32yyoi1d1baas3hzevppfnh99w15r5.png)
![y=-x^2+9x-5](https://img.qammunity.org/2021/formulas/mathematics/high-school/b25n0uyl5o0fwcbrqd066wrgb6yb1nr86n.png)
Therefore, the required equation in standard form is
.