2 Answers

Ellis Michael · Answer 1 · 2023-03-13T12:35:53+0000

Answer:

$(35\left( 1 + 35\right) )/(2)$

Explanation:

a(n) = n is an arithmetic sequence with first term a₁ = 1 and common difference r = 1.

Here we have to calculate the sum of the first 35 consecutive terms of an arithmetic sequence.

Using the formula for the sum ,we get :

$\sum^(q)_(n=p) a_(n)=\frac{\text{number of terms} * \left( \text{first term} +\text{last term} \right) }{2}$

Therefore

$\sum^(35)_(n=1) n=(35\left( 1 + 35\right) )/(2)$

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