Given:
A line passes through two points are (3,1) and (7,-7).
To find:
The equation of the line.
Solution:
The line passes through two points are (3,1) and (7,-7). So, the equation of line is
![y-y_1=(y_2-y_1)/(x_2-x_1)(x-x_1)](https://img.qammunity.org/2021/formulas/mathematics/college/2ft4curll9g1xqqt5yfsd57zfqfj5z775i.png)
![y-1=(-7-1)/(7-3)(x-3)](https://img.qammunity.org/2021/formulas/mathematics/high-school/fu6artcnscazh35lzcrhegtvut2rashqxr.png)
![y-1=(-8)/(4)(x-3)](https://img.qammunity.org/2021/formulas/mathematics/high-school/hgdy5wvjwgbg21rv2li5oxkwe88a1unup8.png)
![y-1=-2(x-3)](https://img.qammunity.org/2021/formulas/mathematics/high-school/s4j6bmwa69u8g4ss5zpu7h4btjrrm16acm.png)
Using distributive property, we get
![y-1=-2(x)-2(-3)](https://img.qammunity.org/2021/formulas/mathematics/high-school/omo3aa9h542hi797wlvayzu4zv4owpbw3i.png)
![y-1=-2x+6](https://img.qammunity.org/2021/formulas/mathematics/high-school/897xbse2mp94xvo3lsyrk4x1ofln2hgx2b.png)
Adding 1 on both sides, we get
![y=-2x+6+1](https://img.qammunity.org/2021/formulas/mathematics/high-school/sdnd2vowq3ads5zd5zqcmh7ajjuw61xcli.png)
![y=-2x+7](https://img.qammunity.org/2021/formulas/mathematics/high-school/z1btwfdwe2hlj7olm531oknx4trrh43xp2.png)
Therefore, the equation of line is
. So, the missing values are -2 and 7 respectively.