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Find the equation of the line

passing through the points (3,1)
and (7,-7).
y = [? ]x + []

Find the equation of the line passing through the points (3,1) and (7,-7). y = [? ]x-example-1
User Jingteng
by
8.0k points

1 Answer

4 votes

Given:

A line passes through two points are (3,1) and (7,-7).

To find:

The equation of the line.

Solution:

The line passes through two points are (3,1) and (7,-7). So, the equation of line is


y-y_1=(y_2-y_1)/(x_2-x_1)(x-x_1)


y-1=(-7-1)/(7-3)(x-3)


y-1=(-8)/(4)(x-3)


y-1=-2(x-3)

Using distributive property, we get


y-1=-2(x)-2(-3)


y-1=-2x+6

Adding 1 on both sides, we get


y=-2x+6+1


y=-2x+7

Therefore, the equation of line is
y=-2x+7. So, the missing values are -2 and 7 respectively.

User Yic
by
8.5k points

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