Answer:
![x = 9.4](https://img.qammunity.org/2021/formulas/mathematics/college/8lgpf3c2ye0ygauf8d4emnspannmst80u2.png)
![y = 17.7](https://img.qammunity.org/2021/formulas/mathematics/college/5afzdf0wgfcw8b3v5cgmbyuyd66m01acju.png)
Explanation:
Given: The figure
Required: Find x and y
The relationship between length x, length 15 and angle 32 is as follows:
![tan \theta = (opp)/(adj)](https://img.qammunity.org/2021/formulas/geography/high-school/hdql1hph2or3lj2s3ca58gvet5rqf0k7la.png)
So, we have:
![tan\ 32= (x)/(15)](https://img.qammunity.org/2021/formulas/mathematics/college/wf1y8ywfyraysnqlpgwrw9gqremg7ana5e.png)
Cross multiply:
![x =15*tan\ 32](https://img.qammunity.org/2021/formulas/mathematics/college/t9zyxzcrqk9xkeh3ucxhltv157qdysl3vl.png)
![x = 15 * 0.6248693519](https://img.qammunity.org/2021/formulas/mathematics/college/y608zmjjw8kvrpekc4rtz8pljt3zzx97f8.png)
![x = 9.3730402785](https://img.qammunity.org/2021/formulas/mathematics/college/vjwlyd5cyt9a79w3vrwkxm5lxxkwnv1z71.png)
--- approximated
Similarly:
The relationship between length y, length 15 and angle 32 is as follows:
![cos \theta = (adj)/(hyp)](https://img.qammunity.org/2021/formulas/geography/high-school/ixyspahvnsmck6x9zp3muky7od9z8wekrf.png)
So, we have:
![cos\ 32= (15)/(y)](https://img.qammunity.org/2021/formulas/mathematics/college/89s4o6hv9eyn3zkl7lqbc34xgm8oyqtpmx.png)
Cross Multiply:
![y * cos\ 32= 15](https://img.qammunity.org/2021/formulas/mathematics/college/5b9ilsjal2pix808iz2lhpqk101xbrderx.png)
Solve for y
![y = (15)/(cos\ 32)](https://img.qammunity.org/2021/formulas/mathematics/college/6d2bfmpwd1mz3o6z3t7ugo3wg8dtg5ukds.png)
![y = (15)/(0.84804809615)](https://img.qammunity.org/2021/formulas/mathematics/college/xm0y8457n6uol91udl3hpjpxs3vagzhb2o.png)
![y = 17.6876760506](https://img.qammunity.org/2021/formulas/mathematics/college/z7a38l2eskjs38u8foipdhd4jxj1w3me1e.png)
--- approximated