Another day, another math problem 3

Anniepoo asked Aug 12, 2023

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Anniepoo asked Aug 12, 2023

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12 votes

Answer:

$2√(x+1)-3\\domain:[-1, \infty)$

Explanation:

$g(h(x)) = 2(√(x+1))-3\\g(h(x)) = 2√(x+1) - 3\\$

the function is only defined when (x+1) >= 0 (since square root) so the domain is when x >= -1

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